15m^2-65m+62=-8

Solution for 15m^2-65m+62=-8 equation:

15m^2-65m+62=-8

We move all terms to the left:

15m^2-65m+62-(-8)=0

We add all the numbers together, and all the variables

15m^2-65m+70=0

a = 15; b = -65; c = +70;
Δ = b2-4ac
Δ = -652-4·15·70
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-5}{2*15}=\frac{60}{30}
=2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+5}{2*15}=\frac{70}{30}
=2+1/3
$